(-2x^2+6x+1)=-2(4x^2-3x+1)

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Solution for (-2x^2+6x+1)=-2(4x^2-3x+1) equation: 



(-2x^2+6x+1)=-2(4x^2-3x+1)

We move all terms to the left:

(-2x^2+6x+1)-(-2(4x^2-3x+1))=0

We get rid of parentheses

-2x^2+6x-(-2(4x^2-3x+1))+1=0



We calculate terms in parentheses: -(-2(4x^2-3x+1)), so:

-2(4x^2-3x+1)

We multiply parentheses

-8x^2+6x-2

Back to the equation:

-(-8x^2+6x-2)



We get rid of parentheses

-2x^2+8x^2-6x+6x+2+1=0

We add all the numbers together, and all the variables

6x^2+3=0

a = 6; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·6·3
Δ = -72
Delta is less than zero, so there is no solution for the equation

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